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mysql中用了lEFt join查询时候数据变多,在线等

(#计算成人人数 SELECT tb_sell_tbfinance.order_no AS order_no0, tb_sell_tbfinance.passenger_type AS passenger_type0, COUNT(*) AS passenger_count FROM tb_sell_tbfinance GROUP BY tb_sell_tbfinance.passenger_type, tb_sell_tbfinance...

左连接是从左表那里返回所有的行,即使在右表中没有匹配的行,如果有多个匹配就会返回多个,所以数据没有变多。

用”SELECT a.*,COUNT(b.`category`) AS product_num FROM (`pl_category` a) LEFT JOIN `pl_product` b ON b.`category` = a.`id` Group By a.`id` ORDER BY a.`id`“ Group By不对,b表里是没有数据的,不能以b表中的category来Group By。

多表联合查询语句:SELECT * FROM table LEFT JOIN ...ON.... WHERE ...ORDER BY ....LIMIT .... 拿laizijiding的例子说明问题:三个表 板块表(block)、帖子表(post)、会员表(user) 如果查询 帖子列表中 帖子 是属于哪个板块和添加帖子的...

select p.name,f.id from fans f left join accounts a on f.fan_account_id=a.id left join deals d on a.id=d.account_idleft join deal_details dd on d.id=dd.deal_id left join products p on dd.relation_object=p.idorder by d.time desc...

左连接a表是主表,c d表是否会被断开和on的条件有关,on的a表就能匹配到

select Sno,Sname,concat(Cname) as Cname from (select sc.Id ,s.Sname, c.Cname from SelectCourse scleft join Student s on s.Sno = sc.Sno left join Course c on c.Cid = sc.Cid) t group by Sno;

是这样的你左边的那个表有近10w数据了。 想快的话就再加一个条件,r.TS_CALL_ID = ??查询值,这样就快了。 因为你现在是全表关联的,index意义不大

无区别left join 是left outer join的简写,left join默认是outer属性的。

select p.name,f.id from fans f left join accounts a on f.fan_account_id=a.id left join deals d on a.id=d.account_idleft join deal_details dd on d.id=dd.deal_id left join products p on dd.relation_object=p.idorder by d.time desc...

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