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thinkphp join whErE

表1.typeid=表2.typeid where(array('表1或表2.userid'=>$where))

$wish = $JOKES->join('inner join user on jokes.uid = user.id')->order('time DESC')->limit($limit)->select();

以一个 user 表和 jifen 表联查为例,, 第一种方式: $data = M('user as a')->join('jifen as b on b.id = a.id')->where('a.id = 1')->select(); 第二种: $data = M()->table('user as a')->join('jifen as b on b.id = a.id')->where(' a.id...

可以写两个join $result = $room->join('left join r_hospital on r_department.hospital_id=r_hospital.id ')->join(' doctor on doctor.id = xx.id')->where($condition)->select();

可以这样 $where['username']=$name; $pkid=$Users->where($where)->select();

这个非常简单,上面的那种情况M('Admin') 默认使用的表就是sx_admin,而你用自己的sx_admin跟自己的sx_admin连接查询肯定会出问题啊!使用下面的吧 $Re = $Admin -> join('LEFT JOIN sx_user ON sx_user.UID = sx_admin.AUID') -> select()

LZ试试别名用数组的方式写: Table方法的参数支持字符串和数组,数组方式的用法: $Model->Table(array('think_user'=>'user','think_group'=>'group'))->where('status>1')->select(); 复制代码 使用数组方式定义的优势是可以避免因为表名和关键...

使用join方法 这是官方实例 $Model = M('Artist'); $Model ->join('think_work ON think_artist.id = think_work.artist_id') ->join('think_card ON think_artist.card_id = think_card.id') ->select();

$name = M('User')->join('LEFT JOIN before_conditions on before_conditions.uid=User.id')->where($mapBarCode)->select(); for($i=0;$iwhere("")->find(); $name[$i]['b_id'] = $name_b['id']; } dump($name); 输出结果user表的id几不会被覆盖

$table=M('表名'); $res=$table->join('表2 on 表1.id=表2.wb_id')->select();

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